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mean free paths

cross section for hydrogen hydrogen collisions can be estimated as 4 \pi R^2 where R is approximately the bohr radius… This gives

\sigma = 3.5 \times 10^{-16} cm^2

The MFP is then l = \frac{1}{n \sigma}

The material leaving the planet is at 1.93 \times 10^{9} cm^{-3} so the MFP is then 1e-7 AU << dx

Posted: 9 years ago
Author: Jonathan
Categories: (none)

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