Changes between Version 170 and Version 171 of FluxLimitedDiffusion

Timestamp:

04/03/13 12:20:28 (12 years ago)

Author:

Jonathan

Comment:

—

FluxLimitedDiffusion

@@ -39 +39 @@
 Now photons don't experience body forces, always travel at the speed of light,  and in general the "collision term" consists of photon emission and absorptions... so we have
 
- [[latex(\frac{\partial}{\partial t} f_\nu + c \mathbf{n} \cdot  \nabla f_\nu  = A_{\nu, \mbox{emiss}} - \chi_\nu f_\nu c  )]] 
-
-where [[latex(A_{\nu,\mbox{emiss}} )]] is the emission rate of photons of frequency [[latex(\nu)]] and the mean free path length is given by [[latex(\chi_\nu = \sigma_nu n)]] where [[latex(\sigma_nu)]] is the particle scattering cross section and [[latex(n)]] is the number density of particles.
+ [[latex(\frac{\partial}{\partial t} f_\nu + c \mathbf{n} \cdot  \nabla f_\nu  = A_{\nu} - \chi_\nu f_\nu c  )]] 
+
+where [[latex(A_{\nu} )]] is the emission rate of photons of frequency [[latex(\nu)]] and the mean free path length is given by [[latex(\chi_\nu = \sigma_\nu n)]] where [[latex(\sigma_\nu)]] is the particle scattering cross section and [[latex(n)]] is the number density of particles.
 
 Now if we multiply through by [[latex( h\nu)]]
@@ -50 +50 @@
 
 where
- [[latex(\eta_\nu = h\nu A_{\nu,\mbox{emiss}})]] is the radiative power
+ [[latex(\eta_\nu = h\nu A_{\nu})]] is the radiative power
 
 If we solve the transport equation along a characteristic