Changes between Version 21 and Version 22 of u/erica/RadHydro
- Timestamp:
- 03/30/16 11:48:42 (9 years ago)
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u/erica/RadHydro
v21 v22 76 76 [[latex($\frac{\partial E}{\partial t} = \nabla \cdot (\frac{c \lambda}{\kappa_R \rho} \nabla E) + \kappa_P \rho (4 \pi B - c E)$)]] 77 77 78 Thus, a zone adjacent to the source will acquire some E due to the sink (through the diffusion term) , plus from BB radiation of the ambient medium (through the coupling term). The relative contributions depend on the strengths of the various opacities,as well as the gradient in E. Here is the grid after the radiative time step:78 Thus, a zone adjacent to the source will acquire some E due to the sink (through the diffusion term). This is because of the gradient in E. There will be no contribution from BB radiation, as out there, E=B. Note, the strength of the diffusion depends on [[latex($\kappa_R$)]] as well as the gradient in E. Here is the grid after the radiative time step: 79 79 80 80 [[Image(trad.png, 35%)]] … … 94 94 [[Image(heatingregions.png, 40%)]] 95 95 96 This process will continue until equilibrium has been reached -- that is, no more gradients in E (and thus no more diffusion), and the energy in the radiative field matches the energy being produced by the blackbody (i.e. E=B). 96 This process will continue until equilibrium has been reached -- that is, no more gradients in E (and thus no more diffusion), and the energy in the radiative field matches the energy being produced by the blackbody (i.e. E=B). Recall, the ambient will not change because out there the only term in E is the BB contribution. That is, E=B out in the ambient, and thus, no changes occur there.