Having a kinetic energy (per unit mass) at r that is higher than would have been acquired from freefall alone, i.e. solving the equation:

ke(r)-\frac{G*M}{r}+\frac{G*M}{R} = 1.01 (\frac{GM}{R})

again where,

ke(R)=ke(r)-\frac{G*M}{r}+\frac{G*M}{R}

ke(r)	Distance (pc)	Error (%)
10*freefall	6.8x10-7	30
100*freefall	7.4x10-6	30
1000*freefall	7.5x10-5	30
10*freefall	.00002	.01
100*freefall	.0002	.01
1000*freefall	.002	.01