Changes between Version 1 and Version 2 of u/johannjc/scratchpad10


Ignore:
Timestamp:
01/08/16 23:53:05 (9 years ago)
Author:
Jonathan
Comment:

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  • u/johannjc/scratchpad10

    v1 v2  
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     10312.)
     104
     105$Q = m C_v \Delta T$
     106
     107$Q = 10 g \times (.092 C/g/^{\circ} C) \times (100 ^{\circ} ) = 92 C$
     108
     109Specific heat of water is
     110
     111 $1 C/g/^{\circ} C$
     112
     113so it would take $1000 C$ to heat 10g of water 100 degrees C
     114
     11513.) 
     116
     117 $\Delta T = \frac{Q}{m C_v} = \frac{1000 J}{1 kg \times 4.184 J/g/^{\circ}C} = .239 ^{\circ}C$