Changes between Version 1 and Version 2 of u/johannjc/scratchpad10
- Timestamp:
- 01/08/16 23:53:05 (9 years ago)
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u/johannjc/scratchpad10
v1 v2 101 101 102 102 103 103 12.) 104 105 $Q = m C_v \Delta T$ 106 107 $Q = 10 g \times (.092 C/g/^{\circ} C) \times (100 ^{\circ} ) = 92 C$ 108 109 Specific heat of water is 110 111 $1 C/g/^{\circ} C$ 112 113 so it would take $1000 C$ to heat 10g of water 100 degrees C 114 115 13.) 116 117 $\Delta T = \frac{Q}{m C_v} = \frac{1000 J}{1 kg \times 4.184 J/g/^{\circ}C} = .239 ^{\circ}C$