\frac{d n}{dt} = (1+bn1) n

\frac{d e}{dt} = c1 n -ae e

n(t)=e^{(1+bn1) t}

e(t) = \frac{c1}{1+bn1} n(t)(1-ae) -e^{ae t}

\frac{de}{dt}=(1-ae)c1 n(t) -ae e^{aet} = c1 n(t)- ae(c1n(t)+e^{aet})