Changes between Version 8 and Version 9 of u/johannjc/scratchpad4


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Timestamp:
09/30/15 17:11:50 (9 years ago)
Author:
Jonathan
Comment:

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  • u/johannjc/scratchpad4

    v8 v9  
    8181We can also write the equation as
    8282
    83 $\beta = \alpha_0 T'_0 + \displaystyle \sum_{\pm j} \alpha_{\pm j} T'_{\pm \hat{j}} + \sum_{\pm i, \pm j,|i| \ne |j|} \alpha_{\pm i, \pm j} T'_{\pm \hat{i} \pm \hat{j}}$
     83$-T_0 - \alpha_0 T^{\lambda+1}_0 - \displaystyle \sum_{\pm j} \alpha_{\pm j} T^{\lambda+1}_{\pm \hat{j}} - \sum_{\pm i, \pm j,|i| \ne |j|} \alpha_{\pm i, \pm j} T^{\lambda+1}_{\pm \hat{i} \pm \hat{j}} = -T'_0 + \alpha_0 T^{\lambda}_0T'_0 + \displaystyle \sum_{\pm j} \alpha_{\pm j} T^{\lambda}_{\pm \hat{j}} T'_{\pm \hat{j}} + \sum_{\pm i, \pm j,|i| \ne |j|} \alpha_{\pm i, \pm j} T^{\lambda}_{\pm \hat{i} \pm \hat{j}} T'_{\pm \hat{i} \pm \hat{j}}$
    8484
    85 and then work out the coefficients for the matrix equation
     85where
    8686
    8787$\alpha_0 = -\frac{1}{\Delta t} -\frac{2E_{jj}}{\Delta x^2}T_0^\lambda$